2k^2+4k=2k(k+2)

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Solution for 2k^2+4k=2k(k+2) equation: 


Simplifying
2k2 + 4k = 2k(k + 2)

Reorder the terms:
4k + 2k2 = 2k(k + 2)

Reorder the terms:
4k + 2k2 = 2k(2 + k)
4k + 2k2 = (2 * 2k + k * 2k)
4k + 2k2 = (4k + 2k2)

Add '-4k' to each side of the equation.
4k + -4k + 2k2 = 4k + -4k + 2k2

Combine like terms: 4k + -4k = 0
0 + 2k2 = 4k + -4k + 2k2
2k2 = 4k + -4k + 2k2

Combine like terms: 4k + -4k = 0
2k2 = 0 + 2k2
2k2 = 2k2

Add '-2k2' to each side of the equation.
2k2 + -2k2 = 2k2 + -2k2

Combine like terms: 2k2 + -2k2 = 0
0 = 2k2 + -2k2

Combine like terms: 2k2 + -2k2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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